Formula Ledger /sym/7ab403
id=1 · host=findroms.cloud · 2026-10-19 02:36Z
∑_{k=1}^{n} k = n(n+1)/2
10x² + 6x + 4 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
368K
E = mc²
∫₀^∞ e^(-φ²) dφ = √π / 2
4K
∑_{k=1}^{n} k = n(n+1)/2
40K
det| 7 4 ; 4 8 | = 40
162K
det| 1 2 ; 7 2 | = -12
68K
∫₀^∞ e^(-t²) dt = √π / 2
65K