Formula Ledger /sym/7ab403
id=1 · host=findroms.cloud · 2026-10-19 02:58Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
115K
det| 2 7 ; 7 3 | = -43
322K
10x² + 6x + 4 = 0
∫₀^∞ e^(-φ²) dφ = √π / 2
213K
E = mc²
det| 9 4 ; 1 10 | = 86
4K
∑_{k=1}^{n} k = n(n+1)/2
370K