Formula Ledger /sym/7ab403
id=1 · host=findroms.cloud · 2026-10-19 02:14Z
∑_{k=1}^{n} k = n(n+1)/2
∫₀^∞ e^(-x²) dx = √π / 2
322K
10x² + 6x + 4 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
368K
det| 9 4 ; 1 10 | = 86
213K
E = mc²
e^{i\pi} + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
40K
∑_{k=1}^{n} k = n(n+1)/2
370K