Formula Ledger /sym/7ab403
id=1 · host=findroms.cloud · 2026-10-19 02:43Z
∑_{k=1}^{n} k = n(n+1)/2
10x² + 6x + 4 = 0
∫₀^∞ e^(-x²) dx = √π / 2
213K
E = mc²
det| 2 2 ; 4 3 | = -2
331K
e^{i\pi} + 1 = 0
det| 11 2 ; 5 12 | = 122
40K
4α² + 2α + 0 = 0
det| 5 7 ; 2 6 | = 16
162K
e^{i\pi} + 1 = 0
iħ ∂ψ/∂t = Ĥψ
∑_{k=1}^{n} k = n(n+1)/2