Formula Ledger /sym/7ab403
id=1 · host=findroms.cloud · 2026-10-19 02:42Z
∑_{k=1}^{n} k = n(n+1)/2
Fe₂O₃ + 3CO → 2Fe + 3CO₂
115K
10x² + 6x + 4 = 0
∫₀^∞ e^(-x²) dx = √π / 2
213K
E = mc²
Fe₂O₃ + 3CO → 2Fe + 3CO₂
331K
e^{i\pi} + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
40K
det| 7 4 ; 4 8 | = 40
370K
4α² + 2α + 0 = 0
Fe₂O₃ + 3CO → 2Fe + 3CO₂
162K
e^{i\pi} + 1 = 0
iħ ∂ψ/∂t = Ĥψ
∑_{k=1}^{n} k = n(n+1)/2