Formula Ledger /sym/7ab403
id=1 · host=findroms.cloud · 2026-10-19 02:38Z
∑_{k=1}^{n} k = n(n+1)/2
10x² + 6x + 4 = 0
Fe₂O₃ + 3CO → 2Fe + 3CO₂
213K
E = mc²
∫₀^∞ e^(-ψ²) dψ = √π / 2
331K
det| 9 4 ; 1 10 | = 86
4K
e^{i\pi} + 1 = 0
Fe₂O₃ + 3CO → 2Fe + 3CO₂
40K
4α² + 2α + 0 = 0