Formula Ledger /sym/7ab403
id=1 · host=findroms.cloud · 2026-10-19 02:38Z
∑_{k=1}^{n} k = n(n+1)/2
10x² + 6x + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
368K
E = mc²
det| 2 2 ; 4 3 | = -2
331K
det| 9 4 ; 1 10 | = 86
4K
e^{i\pi} + 1 = 0
∫₀^∞ e^(-α²) dα = √π / 2
370K
4α² + 2α + 0 = 0
e^{i\pi} + 1 = 0
iħ ∂ψ/∂t = Ĥψ
∑_{k=1}^{n} k = n(n+1)/2