Formula Ledger /sym/7ab403
id=1 · host=findroms.cloud · 2026-10-19 02:37Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
322K
10x² + 6x + 4 = 0
det| 1 1 ; 5 2 | = -3
368K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
213K
E = mc²
∫₀^∞ e^(-y²) dy = √π / 2
331K
e^{i\pi} + 1 = 0
∫₀^∞ e^(-ψ²) dψ = √π / 2
40K
∑_{k=1}^{n} k = n(n+1)/2
162K