Formula Ledger /sym/7ab403
id=1 · host=findroms.cloud · 2026-10-20 07:46Z
d/dz [z^9] = 9z^8
∑_{k=1}^{n} k = n(n+1)/2
218K
det| 3 6 ; 0 4 | = 12
det| 7 4 ; 4 8 | = 40
248K
∑_{k=1}^{n} k = n(n+1)/2
det| 11 4 ; 5 12 | = 112
170K
det| 3 9 ; 1 4 | = 3
244K
∑_{k=1}^{n} k = n(n+1)/2
105K