Formula Ledger /sym/7ab403
id=1 · host=findroms.cloud · 2026-10-19 02:36Z
∑_{k=1}^{n} k = n(n+1)/2
10x² + 6x + 4 = 0
Fe₂O₃ + 3CO → 2Fe + 3CO₂
213K
E = mc²
det| 9 4 ; 1 10 | = 86
4K
e^{i\pi} + 1 = 0
det| 11 2 ; 5 12 | = 122
40K
4α² + 2α + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
162K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
68K
iħ ∂ψ/∂t = Ĥψ
∑_{k=1}^{n} k = n(n+1)/2
8γ² + 4γ + 4 = 0