Formula Ledger /sym/7ab403
id=1 · host=findroms.cloud · 2026-10-19 02:14Z
∑_{k=1}^{n} k = n(n+1)/2
det| 2 2 ; 4 3 | = -2
322K
10x² + 6x + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
368K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
213K
E = mc²
∫₀^∞ e^(-θ²) dθ = √π / 2
331K
e^{i\pi} + 1 = 0
det| 7 4 ; 4 8 | = 40
40K
4α² + 2α + 0 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
162K