Formula Ledger /sym/7ab403
id=1 · host=findroms.cloud · 2026-10-19 02:35Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
115K
det| 9 4 ; 1 10 | = 86
322K
10x² + 6x + 4 = 0
Fe₂O₃ + 3CO → 2Fe + 3CO₂
368K
E = mc²
det| 12 1 ; 4 13 | = 152
4K
e^{i\pi} + 1 = 0
det| 5 7 ; 2 6 | = 16
40K
4α² + 2α + 0 = 0
det| 1 8 ; 4 2 | = -30
162K
iħ ∂ψ/∂t = Ĥψ
∑_{k=1}^{n} k = n(n+1)/2