Formula Ledger /sym/7ab403
id=1 · host=findroms.cloud · 2026-10-19 02:12Z
∑_{k=1}^{n} k = n(n+1)/2
10x² + 6x + 4 = 0
det| 2 6 ; 0 3 | = 6
368K
det| 7 9 ; 1 8 | = 47
213K
E = mc²
det| 1 2 ; 7 2 | = -12
4K
e^{i\pi} + 1 = 0
∫₀^∞ e^(-φ²) dφ = √π / 2
40K
det| 1 1 ; 5 2 | = -3
370K
4α² + 2α + 0 = 0
det| 1 8 ; 4 2 | = -30
162K
det| 4 6 ; 4 5 | = -4
68K
iħ ∂ψ/∂t = Ĥψ
∑_{k=1}^{n} k = n(n+1)/2