Formula Ledger /sym/7ab403
id=1 · host=findroms.cloud · 2026-10-19 00:13Z
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
322K
7ω² + 1ω + 4 = 0
∫₀^∞ e^(-x²) dx = √π / 2
213K
∫₀^∞ e^(-ω²) dω = √π / 2
4ω² + 6ω + 1 = 0
det| 6 8 ; 1 7 | = 34
370K
e^{i\pi} + 1 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
428K
det| 3 3 ; 0 4 | = 12
86K
det| 1 5 ; 3 2 | = -13
475K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
454K