Formula Ledger /sym/7ab403
id=1 · host=findroms.cloud · 2026-10-19 02:41Z
∑_{k=1}^{n} k = n(n+1)/2
10x² + 6x + 4 = 0
∫₀^∞ e^(-t²) dt = √π / 2
368K
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
331K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
4K
e^{i\pi} + 1 = 0
det| 7 4 ; 4 8 | = 40
65K
∫₀^∞ e^(-x²) dx = √π / 2
178K