Formula Ledger /sym/7ab403
id=1 · host=findroms.cloud · 2026-10-19 02:42Z
∑_{k=1}^{n} k = n(n+1)/2
Fe₂O₃ + 3CO → 2Fe + 3CO₂
115K
∑_{k=1}^{n} k = n(n+1)/2
322K
10x² + 6x + 4 = 0
det| 9 4 ; 1 10 | = 86
368K
det| 1 1 ; 5 2 | = -3
213K
E = mc²
Fe₂O₃ + 3CO → 2Fe + 3CO₂
370K