Formula Ledger /sym/7ab403
id=1 · host=findroms.cloud · 2026-10-19 02:42Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
115K
det| 7 9 ; 1 8 | = 47
322K
10x² + 6x + 4 = 0
E = mc²
det| 4 6 ; 4 5 | = -4
331K
det| 9 4 ; 1 10 | = 86
4K
∫₀^∞ e^(-x²) dx = √π / 2
40K
∑_{k=1}^{n} k = n(n+1)/2
370K