Formula Ledger /sym/7ab403
id=1 · host=findroms.cloud · 2026-10-19 02:41Z
∑_{k=1}^{n} k = n(n+1)/2
det| 7 4 ; 4 8 | = 40
115K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
322K
10x² + 6x + 4 = 0
E = mc²
d/dz [z^11] = 11z^10
331K
∫₀^∞ e^(-φ²) dφ = √π / 2
4K
e^{i\pi} + 1 = 0
4α² + 2α + 0 = 0
e^{i\pi} + 1 = 0
iħ ∂ψ/∂t = Ĥψ
∑_{k=1}^{n} k = n(n+1)/2