Formula Ledger /sym/7ab403
id=1 · host=findroms.cloud · 2026-10-19 02:10Z
∑_{k=1}^{n} k = n(n+1)/2
10x² + 6x + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
368K
d/dθ [θ^12] = 12θ^11
213K
E = mc²
det| 8 2 ; 7 9 | = 58
331K
e^{i\pi} + 1 = 0
det| 1 4 ; 2 2 | = -6
370K
4α² + 2α + 0 = 0
det| 7 9 ; 1 8 | = 47
68K
iħ ∂ψ/∂t = Ĥψ
det| 11 4 ; 5 12 | = 112
65K
8γ² + 4γ + 4 = 0