Formula Ledger /sym/7ab403
id=1 · host=findroms.cloud · 2026-10-19 02:39Z
∑_{k=1}^{n} k = n(n+1)/2
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
115K
det| 7 4 ; 4 8 | = 40
322K
10x² + 6x + 4 = 0
det| 12 1 ; 4 13 | = 152
213K
E = mc²
Fe₂O₃ + 3CO → 2Fe + 3CO₂
331K
∑_{k=1}^{n} k = n(n+1)/2
4K
e^{i\pi} + 1 = 0