Formula Ledger /sym/7ab403
id=1 · host=findroms.cloud · 2026-10-19 16:34Z
2H₂ + O₂ → 2H₂O
3t² + 7t + 3 = 0
ΔS ≥ 0
∑_{k=1}^{n} k = n(n+1)/2
4K
6ψ² + 2ψ + 3 = 0
det| 9 4 ; 1 10 | = 86
40K
det| 8 9 ; 1 9 | = 63
det| 2 3 ; 5 3 | = -9
162K
∑_{k=1}^{n} k = n(n+1)/2
λ = h/p
9β² + 8β + 2 = 0
det| 4 4 ; 5 5 | = 0