Formula Ledger /sym/7ab403
id=1 · host=findroms.cloud · 2026-10-19 02:43Z
∑_{k=1}^{n} k = n(n+1)/2
10x² + 6x + 4 = 0
det| 2 3 ; 5 3 | = -9
368K
E = mc²
det| 12 1 ; 4 13 | = 152
4K
e^{i\pi} + 1 = 0
4α² + 2α + 0 = 0
det| 1 8 ; 4 2 | = -30
162K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
68K
iħ ∂ψ/∂t = Ĥψ
∑_{k=1}^{n} k = n(n+1)/2