Formula Ledger /sym/7ab403
id=1 · host=findroms.cloud · 2026-10-20 07:41Z
d/dz [z^9] = 9z^8
∑_{k=1}^{n} k = n(n+1)/2
218K
det| 3 6 ; 0 4 | = 12
det| 1 8 ; 4 2 | = -30
248K
det| 4 6 ; 4 5 | = -4
157K
∑_{k=1}^{n} k = n(n+1)/2
det| 2 4 ; 5 3 | = -14
det| 9 4 ; 1 10 | = 86
244K
e^{i\pi} + 1 = 0
det| 5 7 ; 2 6 | = 16
100K
∑_{k=1}^{n} k = n(n+1)/2
138K
∫₀^∞ e^(-ψ²) dψ = √π / 2
354K
det| 7 2 ; 7 8 | = 42
433K