Formula Ledger /sym/7ab403
id=1 · host=findroms.cloud · 2026-10-19 02:38Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
115K
det| 4 2 ; 1 5 | = 18
322K
10x² + 6x + 4 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
213K
E = mc²
det| 9 4 ; 1 10 | = 86
4K
det| 1 2 ; 7 2 | = -12
40K
∑_{k=1}^{n} k = n(n+1)/2
370K