Formula Ledger /sym/7ab403
id=1 · host=findroms.cloud · 2026-10-19 02:42Z
∑_{k=1}^{n} k = n(n+1)/2
10x² + 6x + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
213K
E = mc²
∫₀^∞ e^(-θ²) dθ = √π / 2
331K
e^{i\pi} + 1 = 0
4α² + 2α + 0 = 0
e^{i\pi} + 1 = 0
iħ ∂ψ/∂t = Ĥψ
∑_{k=1}^{n} k = n(n+1)/2
8γ² + 4γ + 4 = 0