Formula Ledger /sym/7ab403
id=1 · host=findroms.cloud · 2026-10-19 00:36Z
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
322K
7ω² + 1ω + 4 = 0
det| 1 1 ; 5 2 | = -3
368K
∫₀^∞ e^(-ω²) dω = √π / 2
det| 5 6 ; 4 6 | = 6
331K
4ω² + 6ω + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
370K
det| 12 1 ; 4 13 | = 152
162K
det| 9 4 ; 1 10 | = 86
68K