Formula Ledger /sym/7ab403
id=1 · host=findroms.cloud · 2026-10-19 02:56Z
∑_{k=1}^{n} k = n(n+1)/2
CH₄ + 2O₂ → CO₂ + 2H₂O
322K
10x² + 6x + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
368K
det| 2 8 ; 7 3 | = -50
213K
E = mc²
e^{i\pi} + 1 = 0
∫₀^∞ e^(-x²) dx = √π / 2
40K
det| 5 6 ; 4 6 | = 6
370K
4α² + 2α + 0 = 0
det| 11 2 ; 5 12 | = 122
162K
det| 9 4 ; 1 10 | = 86
68K
iħ ∂ψ/∂t = Ĥψ
∑_{k=1}^{n} k = n(n+1)/2
8γ² + 4γ + 4 = 0
2t² + 7t + 7 = 0