Formula Ledger /sym/7ab403
id=1 · host=findroms.cloud · 2026-10-19 00:34Z
ω = 2πf
7ω² + 1ω + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
368K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
213K
∫₀^∞ e^(-ω²) dω = √π / 2
det| 3 9 ; 1 4 | = 3
331K
4ω² + 6ω + 1 = 0
det| 7 4 ; 4 8 | = 40
40K
e^{i\pi} + 1 = 0