Formula Ledger /sym/7ab403
id=1 · host=findroms.cloud · 2026-10-19 16:50Z
2H₂ + O₂ → 2H₂O
3t² + 7t + 3 = 0
∫₀^∞ e^(-t²) dt = √π / 2
368K
∑_{k=1}^{n} k = n(n+1)/2
213K
ΔS ≥ 0
∑_{k=1}^{n} k = n(n+1)/2
331K
CH₄ + 2O₂ → CO₂ + 2H₂O
4K
6ψ² + 2ψ + 3 = 0
det| 12 1 ; 4 13 | = 152
370K
det| 5 6 ; 4 6 | = 6
162K
det| 7 4 ; 4 8 | = 40
65K