Formula Ledger /sym/7ab403
id=1 · host=findroms.cloud · 2026-10-19 02:41Z
∑_{k=1}^{n} k = n(n+1)/2
10x² + 6x + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
368K
det| 2 3 ; 5 3 | = -9
213K
E = mc²
e^{i\pi} + 1 = 0
4α² + 2α + 0 = 0
iħ ∂ψ/∂t = Ĥψ
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
65K
det| 7 2 ; 3 8 | = 50
178K
8γ² + 4γ + 4 = 0
2t² + 7t + 7 = 0