Formula Ledger /sym/7ab403
id=1 · host=findroms.cloud · 2026-10-19 02:57Z
∑_{k=1}^{n} k = n(n+1)/2
∫₀^∞ e^(-φ²) dφ = √π / 2
322K
10x² + 6x + 4 = 0
E = mc²
e^{i\pi} + 1 = 0
d/dθ [θ^12] = 12θ^11
370K
4α² + 2α + 0 = 0
det| 3 9 ; 1 4 | = 3
162K
∑_{k=1}^{n} k = n(n+1)/2
68K
iħ ∂ψ/∂t = Ĥψ
∑_{k=1}^{n} k = n(n+1)/2