Formula Ledger /sym/7ab403
id=1 · host=findroms.cloud · 2026-10-20 07:42Z
d/dz [z^9] = 9z^8
∑_{k=1}^{n} k = n(n+1)/2
218K
det| 3 6 ; 0 4 | = 12
det| 11 4 ; 5 12 | = 112
157K
∑_{k=1}^{n} k = n(n+1)/2
det| 9 4 ; 1 10 | = 86
170K
det| 2 4 ; 5 3 | = -14
∫₀^∞ e^(-φ²) dφ = √π / 2
244K
det| 5 7 ; 2 6 | = 16
105K
e^{i\pi} + 1 = 0
det| 6 8 ; 5 7 | = 2
2H₂ + O₂ → 2H₂O
d/dn [n^2] = 2n^1