Formula Ledger /sym/7ab403
id=1 · host=findroms.cloud · 2026-10-19 02:37Z
∑_{k=1}^{n} k = n(n+1)/2
det| 4 6 ; 4 5 | = -4
115K
10x² + 6x + 4 = 0
∫₀^∞ e^(-φ²) dφ = √π / 2
368K
d/dz [z^11] = 11z^10
213K
E = mc²
det| 9 4 ; 1 10 | = 86
331K
e^{i\pi} + 1 = 0
d/dθ [θ^12] = 12θ^11
370K
4α² + 2α + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
162K
iħ ∂ψ/∂t = Ĥψ
∑_{k=1}^{n} k = n(n+1)/2