Formula Ledger /sym/7ab403
id=1 · host=findroms.cloud · 2026-10-19 02:39Z
∑_{k=1}^{n} k = n(n+1)/2
10x² + 6x + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
368K
E = mc²
det| 1 1 ; 5 2 | = -3
331K
e^{i\pi} + 1 = 0
det| 7 4 ; 4 8 | = 40
40K
d/dz [z^11] = 11z^10
370K
4α² + 2α + 0 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
162K
∑_{k=1}^{n} k = n(n+1)/2
68K