Formula Ledger /sym/7ab403
id=1 · host=findroms.cloud · 2026-10-20 07:42Z
d/dz [z^9] = 9z^8
∑_{k=1}^{n} k = n(n+1)/2
218K
det| 3 6 ; 0 4 | = 12
det| 11 2 ; 5 12 | = 122
248K
det| 9 4 ; 1 10 | = 86
157K
∑_{k=1}^{n} k = n(n+1)/2
∫₀^∞ e^(-α²) dα = √π / 2
170K
∫₀^∞ e^(-y²) dy = √π / 2
299K
det| 2 4 ; 5 3 | = -14
∑_{k=1}^{n} k = n(n+1)/2
244K