Formula Ledger /sym/7ab403
id=1 · host=findroms.cloud · 2026-10-19 00:36Z
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
115K
7ω² + 1ω + 4 = 0
∫₀^∞ e^(-φ²) dφ = √π / 2
213K
∫₀^∞ e^(-ω²) dω = √π / 2
det| 4 6 ; 4 5 | = -4
331K
det| 9 4 ; 1 10 | = 86
4K
∑_{k=1}^{n} k = n(n+1)/2
370K