Formula Ledger /sym/7ab403
id=1 · host=findroms.cloud · 2026-10-19 02:41Z
∑_{k=1}^{n} k = n(n+1)/2
10x² + 6x + 4 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
368K
E = mc²
e^{i\pi} + 1 = 0
4α² + 2α + 0 = 0
det| 2 6 ; 0 3 | = 6
162K
iħ ∂ψ/∂t = Ĥψ
∑_{k=1}^{n} k = n(n+1)/2
8γ² + 4γ + 4 = 0
2t² + 7t + 7 = 0