Formula Ledger /sym/7ab403
id=1 · host=findroms.cloud · 2026-10-19 02:35Z
∑_{k=1}^{n} k = n(n+1)/2
10x² + 6x + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
368K
det| 9 4 ; 1 10 | = 86
213K
E = mc²
d/dz [z^11] = 11z^10
331K
e^{i\pi} + 1 = 0
4α² + 2α + 0 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
162K
e^{i\pi} + 1 = 0
iħ ∂ψ/∂t = Ĥψ
∑_{k=1}^{n} k = n(n+1)/2