Formula Ledger /sym/7ab403
id=1 · host=findroms.cloud · 2026-10-19 16:52Z
2H₂ + O₂ → 2H₂O
3t² + 7t + 3 = 0
∫₀^∞ e^(-ψ²) dψ = √π / 2
368K
d/dz [z^11] = 11z^10
213K
ΔS ≥ 0
∑_{k=1}^{n} k = n(n+1)/2
331K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
4K
6ψ² + 2ψ + 3 = 0
det| 9 4 ; 1 10 | = 86
40K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
162K
∫₀^∞ e^(-α²) dα = √π / 2
178K